a b c d e f g are consecutive even numbers…

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a, b, c, d, e, f, g are consecutive even numbers. j, k, l, m, n are consecutive odd numbers. The average of all the numbers is :

  1. A. $$3\left( {\frac{{a + n}}{2}} \right)$$
  2. B. $$\left( {\frac{{1 + d}}{2}} \right)$$
  3. C. $$\left( {\frac{{a + b + m + n}}{4}} \right)$$
  4. D. $$3\left( {\frac{{j + c + n +g}}{4}} \right)$$

Answer: Option B

Here is complete explanation of a b c d e f g are consecutive even numbers….

Solution(By ExamCraze Team)

According to the question,
Consecutive even numbers
= a, b, c, d, e, f, g
Consecutive odd numbers
= j, k, l, m, n
Consecutive even numbers
2, 4, 6, 8, 10, 12, 14
$$frac{2 + 4 + 6 + 8 + 10 + 12 + 14}{7}$$
= $$frac{56}{7}$$
= 8 middle term
Consecutive odd numbers
1, 3, 5, 7, 9
$$frac{1 + 3 + 5 + 7 + 9}{2}$$
= $$frac{25}{5}$$
= 5 middle term
∴ Same as in above situation.
Average of even numbers = d
Average of odd numbers = 1
∴ Average of all numbers = $$frac{1 + d}{2}$$

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