A student was asked to find the arithmetic mean of the…

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A student was asked to find the arithmetic mean of the numbers 3, 11, 7, 9, 15, 13, 8, 19, 17, 21, 14 and x. He found mean to be 12. What should be the number in place of x?

  1. A. 3
  2. B. 7
  3. C. 17
  4. D. 31

Answer: Option B

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Solution(By ExamCraze Team)

Clearly, we have
$$ Rightarrow frac{{3 + 11 + 7 + 9 + 15 + 13 + 8 + 19 + 17 + 21 + 14 + x}}{{12}} = 12$$
$$eqalign{ & Rightarrow 137 + x = 144 cr & Rightarrow x = 144 - 137 cr & Rightarrow x = 7 cr} $$

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