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### Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:

- A. 20
- B. 21
- C. 28
- D. 32

**Answer: Option C **

Here is complete explanation of Ajit has a certain average for 9 innings In the tenth….

__Solution(By ExamCraze Team)__

Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.

In the 10^{th} inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings.

Now,

$$eqalign{
& Rightarrow 9x + 100 = 10 times left( {x + 8} right) cr
& {text{or}},,9x + 100 = 10x + 80 cr
& {text{or}},,x = 100 - 80 cr
& {text{or}},,x = 20 cr
& {text{New}},{text{average}} = left( {x + 8} right) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = 28,{text{runs}} cr} $$