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Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:
- A. 20
- B. 21
- C. 28
- D. 32
Answer: Option C
Here is complete explanation of Ajit has a certain average for 9 innings In the tenth….
Solution(By ExamCraze Team)
Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings.
Now,
$$eqalign{
& Rightarrow 9x + 100 = 10 times left( {x + 8} right) cr
& {text{or}},,9x + 100 = 10x + 80 cr
& {text{or}},,x = 100 - 80 cr
& {text{or}},,x = 20 cr
& {text{New}},{text{average}} = left( {x + 8} right) cr
& ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = 28,{text{runs}} cr} $$
