Ajit has a certain average for 9 innings In the tenth…

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Ajit has a certain average for 9 innings. In the tenth innings, he scores 100 runs thereby increasing his average by 8 runs. His new average is:

  1. A. 20
  2. B. 21
  3. C. 28
  4. D. 32

Answer: Option C

Here is complete explanation of Ajit has a certain average for 9 innings In the tenth….

Solution(By ExamCraze Team)

Let Ajit's average be x for 9 innings. So, Ajit scored 9x run in 9 innings.
In the 10th inning, he scored 100 runs then average became (x+8). And he scored (x + 8) × 10 runs in 10 innings.
Now,
$$eqalign{ & Rightarrow 9x + 100 = 10 times left( {x + 8} right) cr & {text{or}},,9x + 100 = 10x + 80 cr & {text{or}},,x = 100 - 80 cr & {text{or}},,x = 20 cr & {text{New}},{text{average}} = left( {x + 8} right) cr & ,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,, = 28,{text{runs}} cr} $$

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