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Average of n numbers is a. The first number is increased by 2, second one is increased by 4, the third one is increased by 8 and so on. The average of the new numbers is –
- A. $$a + \frac{{2\left( {{2^n} – 1} \right)}}{n}$$
- B. $$a + \frac{{{2^{n + 1}} – 1}}{n}$$
- C. $$a + \frac{{{2^{n + 1}}}}{n}$$
- D. $$a + 2\frac{{{2^{n – 1}}}}{n}$$
Answer: Option A
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