Average of ten positive numbers is x If each number is…

Solution(By ExamCraze Team)

Let 10 numbers be x1, x2, x3, . . . . . . . x10
According to question average of these 10 numbers is 10
$$ Rightarrow frac{{ {x1 + x2 + x3 + .... + x10} }}{{10}} = x$$
Now if each number is increased by 10%,
then new average, say y.
$$y = frac{{ {1.1x1 + 1.1x2 + 1.1x3 + .... + 1.1x10} }}{{10}}$$
$${kern 1pt} Rightarrow y = 1.1 times {frac{{ {x1 + x2 + x3 + .... + x10} }}{{10}}} $$
$$eqalign{ & Rightarrow y = 1.1x cr & Rightarrow y,{text{is }}10% ,{text{increased}} cr} $$