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The average of 5 consecutive integers starting with ‘m’ is n.
What is the average of 6 consecutive integers starting with (m + 2)?
- A. $$\frac{(2n + 5)}{2}$$
- B. (2n + 2)
- C. (n + 3)
- D. $$\frac{(2n + 9)}{2}$$
Answer: Option A
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