The average of five different positive numbers is 25 x is…

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The average of five different positive numbers is 25. x is the decrease in the average when the smallest number among them is replaced by 0. What can be said about x?

  1. A. x is less than 5
  2. B. x is greater than 5
  3. C. x is equal to 5
  4. D. Cannot be determined

Answer: Option A

Here is complete explanation of The average of five different positive numbers is 25 x is….

Solution(By ExamCraze Team)

Let a, b, c, d, and e be the five positive numbers in the decreasing order of size such that e is the smallest number.
We are given that the average of the five numbers is 25. Hence, we have the equation $$frac{{{text{a}} + {text{b}} + {text{c}} + {text{d}} + {text{e}}}}{5} = 25$$
a + b + c + d + e = 125 ----------- (1) by multiplying by 5. The smallest number in a set is at least less than the average of the numbers in the set if at least one number is different. For example, the average of 1, 2, and 3 is 2, and the smallest number in the set 1 is less than the average 2. Hence, we have the inequality 0 0 > -e > -25 by multiplying both sides of the inequality by -1 and flipping the directions of the inequalities. Adding this inequality to equation (1) yields 0 + 125 > (a + b + c + d + e) + (-e) > 125 - 25 125 > (a + b + c + d) > 100 125 > (a + b + c + d + 0) > 100 by adding by 0 25 > $$frac{{{text{a}} + {text{b}} + {text{c}} + {text{d}} + 0}}{5}$$     ⇒ 20 by dividing the inequality by 5
25 > The average of numbers a, b, c, d and 0 > 20
Hence, x equals
(Average of the numbers a, b, c, d and e) – (Average of the numbers a, b, c, and d)
= 25 − (A number between 20 and 25)
⇒ A number less than 5
Hence, x is less than 5

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